If it's not what You are looking for type in the equation solver your own equation and let us solve it.
12x^2-13x-22=0
a = 12; b = -13; c = -22;
Δ = b2-4ac
Δ = -132-4·12·(-22)
Δ = 1225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1225}=35$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-13)-35}{2*12}=\frac{-22}{24} =-11/12 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-13)+35}{2*12}=\frac{48}{24} =2 $
| y=+5−y+4 | | x^2+x=4=0 | | 7(x-5)+12=4(x-5) | | (7y+18)(7y+15)=0 | | 5x^2+26x-23=0 | | -248=c253 | | 16x-8x^2=0 | | 4u+9=1 | | 16x-15=3-+11x | | m^2+9m=22 | | -8+10k=72 | | x2-15=21 | | x2-15=51 | | x^2+0.75^2=2^2 | | 48v=1,488 | | -3n=3-5n | | -8y-28+28=-36=28 | | 5x-B=2X+7 | | 2x2+2x-4=0 | | x^2=2^2 | | -2x^2-x-31=0 | | 7=1/3(8x+6) | | 2(x+3)+3=3(x+4)+1 | | 13=y/3+10 | | g=5-4 | | 3x*5=27 | | X(2x+5)=(x+7) | | 3x-7=x-(8x-2) | | 6s=9 | | 2x+5=`12 | | 5q/3-q=2 | | 24y=-14 |